Y=7x^2+26x-8

Solution for Y=7x^2+26x-8 equation:

=7Y^2+26Y-8

We move all terms to the left:

-(7Y^2+26Y-8)=0

We get rid of parentheses

-7Y^2-26Y+8=0

a = -7; b = -26; c = +8;
Δ = b2-4ac
Δ = -262-4·(-7)·8
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-30}{2*-7}=\frac{-4}{-14}
=2/7
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+30}{2*-7}=\frac{56}{-14}
=-4
$